Q:

A recent poll of 380 randomly selected Americans showed that 24% ( = 0.24) are happy with their cell phone carriers. The country’s largest cell phone carrier would like to know, within a 90% confidence level, the margin of error for this poll. (90% confidence level z*-score of 1.645) Remember, the margin of error, E, can be determined using the formula E = z*. To the nearest tenth of a percent, the margin of error for the poll is %.

Accepted Solution

A:
THE ANSWER IS 3.6% BECAUSE I JUST TOOK THE TEST AND GOT A 100%