Define the sets A, B, C, and D as follows:A = {-3, 0, 1, 4, 17}B = {-12, -5, 1, 4, 6}C = {x ∈ Z: x is odd}D = {x ∈ Z: x is positive}For each of the following set expressions, if the corresponding set is finite, express the set using roster notation. Otherwise, indicate that the set is infinite.(a)A ∪ B(b)A ∩ B(c)A ∩ C(d)A ∪ (B ∩ C)(e)A ∩ B ∩ C(f)A ∪ C(g)(A ∪ B) ∩ C(h)A ∪ (C ∩ D)

Answer:(a) A∪B = {-12,-5,-3, 0, 1, 4, 6, 17}(b) A∩B = {1,4}(c) A∩C = {-3,1,17}(d) A ∪ (B ∩ C) = {-5,-3,0,1,4,17}(e) A ∩ B ∩ C = {1}(f)  A ∪ C, the set is infinite.(g) (A ∪ B) ∩ C = {-5,-3,1,17}(h) A ∪ (C ∩ D), the set is infinite.Step-by-step explanation:(a) Recall that the union of A and B is the set that contains all the elements that are in A or in B, and that in set notation no repetitions are allowed, so we can only write 1 once.(b) Recall the the intersection of A and B is the set formed by the elements that are in A and B at the same time. In this case, only 1 and 4 satisfy that condition.(c) In this case we list only the elements in A that are odd.(d) In this case we perform first the operation B ∩ C={-5}. Then, we perform A∪{-5}.(e) Recall that set operations are associative, so A ∩ B ∩ C = (A ∩ B )∩ C. As we have calculated A∩B = {1,4}, we only need to find the odd numbers, which is only 1.(f) The set is infinite because C is infinite. Recall that the union of an infinite set with any other, is infinite too. In plain words, when we perform a union of set we are adding elements.(g) These are the elements that are in A ∪ B and are odd too.(h) Notice that the set C ∩ D is infinite, because is formed by the positive odd integers. So, its union with any other set is infinite too.